Mathematics & Science
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Solving "Impossible" Differential Equations with Mathematica(continued from last page...) Say we wanted to find the value of the initial value problem's solution at a particular value of x. How about at x = 2 for now? Then all we need to do is evaluate sol1 at x = 2 as follows: sol1/.x->2 Go ahead and try it. Come back when you have. Let's see what you should have gotten... |
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ODE Laboratories: A Sabbatical Project by Christopher A. Barker ©2017 San Joaquin Delta College, 5151 Pacific Ave., Stockton, CA 95207, USA e-mail: cbarker@deltacollege.edu |