Mathematics & Science
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Applications of Differential EquationsElectric CircuitsPreliminary Example(continued from last page...) Using Mathematica as a simple calculator you should have gotten:
(0-10*0-1/0.001)/0.25 So our second initial condition now becomes I'(0) = -4000. At last we have a workable initial value problem, namely: L I'' + R I' + I/C = E' I(0) = 0 I'(0) = -4000 Have Mathematica solve it for you, assigning the result into the variable underdamped. Remember I is a reserved Mathematica constant, so you'll have to use i to represent current instead. Also, don't forget to plug in the correct values for L, R, C, and E' (thats E prime not just E), and make the independent variable t, not x. (Obviously in this case, since E(t) = 0, then E'(t) = 0.) Switch back to Mathematica now and get on with it! Let's go see what you should have gotten... |
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ODE Laboratories: A Sabbatical Project by Christopher A. Barker ©2017 San Joaquin Delta College, 5151 Pacific Ave., Stockton, CA 95207, USA e-mail: cbarker@deltacollege.edu |